Ask questions and get helpful answers.

A body vibrates in simple harmonic motion with the frequency of 50hz and amplitude of 4cm, find period, acceleration at the middle and the end of the path of oscillation.

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. I need the solution

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. period is 1/f = 0.02
    y = 0.04 sin (2 pi f t) = 0.04 sin (100 pi t)
    v = 0.04 (100 pi) cos (100 pi t)
    a = -0.04 (100 pi)^2 sin (100 pi t) = - (100 pi)^2 y so acceleration at middle is zero:) and at max is 0.04 (100 pi)^2

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.