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A three-kilogram cannonball is shot out of a cannon with an initial velocity of 300 m/s at a 25o angle. A headwind exerts a constant 5 N horizontal force. How far will the cannonball travel before horizontally hitting the ground?

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  1. vertical problem first, how long in air?
    v = Vi - g t
    v = 300 sin 25 - 9.81 t
    at top v = 0 (half the flight)
    9.81 * t at top = 300 * sin 25
    t at top = 12.9 seconds upward
    so
    total t = 25.8 seconds aloft
    Now horizontal
    a = F/m = -5/3
    v = 300 cos 25 - (5/3) t
    x = 300 cos 25 t - (5/6) t^2
    put in t = 25.8 and you have it

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