Find the second, fourth, and eleventh terms of sequence described by the rule.
A(n) = 3 + (n  1)(5)

A(n) = 3+ (n1)5
A(2) = 3 + (2  1) × 5
A(2) = 3 + 1 × 5
A(2) = 3 + 5
A(2) = 8
Next, I had to find A(4)= ?
So what, I did was:
A(n) = 3 + (n  1)5
From A (4), n = 4
A(4) = 3 + (4  1) × 5
A(4) = 3 + 15
A(4) = 18
However now, I need to find A(11) = ?
Please help me find A(11) = ?
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1 answer

once is enough, please
Repeated postings will not get faster or better responses. 👍
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answered by oobleck
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