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Which of the following are solutions to the given equation on the interval [0,2π)?

cot^3x−cotx=0
Select all that are true. If there are none that are true, do no select any before submitting.

π/6
0
5π/4
3π/4
π
π/3
11π/6
7π/4
π/4
π/2

help please

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2 answers
  1. cot x (cot^2 x - 1) = 0
    when does cot x = 0 ?
    cot x = cos x /sin x
    works at x = pi/2 and x= 3 pi/2
    when does cot^2 x = +1
    cos x = sin x at x = pi/4 and at x = 5 pi/4

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  2. Ok..so what is the answer? Confused

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