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A train starts from rest at a station and accelerates at the rate of 1.4 m/s2. How long does it take the train to cover a 590 m distance?

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2 answers

  1. v = Vi + a t
    x = Xi + Vi t + (1/2) a t^2
    Vi = 0, starts at rest
    a = 1.4 m/s^2
    so
    distance = x - Xi = 590 = 0 t + (1/2)(1.4) t^2
    0.7 t^2 = 590
    t^2 = 843
    t = 29 seconds

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  2. d = 1/2 a t^2

    590 = 1/2 * 1.4 * t^2

    t = √(2 * 590 / 1.4)

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