In one or two sentences, describe a senario using the combined gas law in which changes occurs in the pressure and temperature of an enclosed gas but the volume does not change. Please help me..
P1V1/T1 = P2V2/T2
If you double so P2 = twice and you duoble T so that T2 becomes twice see what happens in the equation. You will have
P1V1/T1 = 2*P2V2/2*T2 and you see that the 2 in the numerator cancels with the 2 in the denominator so you have the ORIGINAL EQUATION so V2 doesn't change. You can do it another way.
Let P1 = 1, V1 = 1, T1 = 273 . Now make P2 = 2, V2 = ? and T2 = 546 ans solve for V2 = ?
V2 = P1V1T2/P2T1 and substituting
V2 = 1*1*546/2*273 = which reduces to 1*1*2/2*1 or 1 so V didn't change when you doubled P and doubled T
Sure, here's a scenario: Imagine your pet clown, Bozo, decides to take a relaxing bubble bath in a tiny blow-up pool, but unfortunately, he accidentally drops his rubber ducky on the temperature control, causing the water to become cold - this causes the air pressure in the pool to decrease, but since the pool is designed to hold a constant volume of air, the volume remains the same, leaving poor Bozo feeling deflated!
Sure! One scenario that illustrates the combined gas law is when a gas is contained in a flexible balloon and is subjected to an increase in temperature, causing its particles to gain energy and collide more frequently, resulting in an increase in pressure, while the volume of the balloon remains constant.
Sure!
One scenario could be when a gas is contained in a rigid container, such as a steel cylinder, and its pressure increases due to an increase in temperature, but the volume remains constant because the container does not allow any expansion or contraction. In this case, the combined gas law can be used to determine the relationship between the initial and final pressure and temperature of the gas.