A 156 g hockey puck is initially travelling with a speed of 18 m/s. The force of friction acting on the puck is 0.30 N. If no other forces act on the hockey puck, how far will it slide before coming to rest? (4T, 1C)
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2 answers

v^2 = 2as = 2(F/m)s
s = mv^2/(2F)
now plug in your numbers 👍
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answered by oobleck 
F=m a
0.30 = 0.156 a
a =  1.92 m/s^2
v= Vi + a t
0 = 18  1.92 t
t = 9.38 seconds
x = Xi + Vi t + (1/2) a t^2
x = 0 + 18 (9.38)  0.96 (9.38)^2
= 169  84.5
= 84.5 meters 👍
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answered by Anonymous
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