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N2 + 3H2 --> 2NH3

If 28 grams of nitrogen reacts with excess hydrogen, how many grams of NH3 will be formed?

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  1. N2 + 3H2 --> 2NH3
    moles N2 = grams/molar mass = (28/2*14) = 1.0
    Convert this to mols NH3 produced by
    1.0 mole N2 x (2 moles NH3/1 mol N2) b= 1.0 x 2/1 = 2.0
    Then grams NH3 = mols NH3 x molar mass NH3 = ?

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