Through (-4, 0), slope = 1/4
y = mx + b
you know m = 1/4
y = (1/4)x + b
you know (-4,0) lies on it
0 = (1/4)(-4) + b
0 = -1 + b
b = 1
y = (1/4)x + 1
or
y - 0 = (1/4)(x+4), using the point-slope form
y = (1/4)x + 1
To find the equation of a line given a point and the slope, you can use the point-slope form of a linear equation. The point-slope form is given as:
y - y1 = m(x - x1)
Where (x1, y1) represents the given point coordinates, and m represents the slope.
In this case, the given point is (-4, 0) and the slope is 1/4. Plugging these values into the point-slope form, we get:
y - 0 = (1/4)(x - (-4))
Simplifying further:
y = (1/4)(x + 4)
Expanding the equation:
y = (1/4)x + (1/4)(4)
Simplifying the right side of the equation:
y = (1/4)x + 1
Therefore, the equation of the line is y = (1/4)x + 1.