find the equation of a parabola with vertex on the line y=2x, axis parallel to the xaxis and passing through (3/2, 1) and (3,4)
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1 answer

since the vertex is on the line y=2x, suppose it is at (h,2h). Then
x = a(y2h)^2 + h
Now use the points to get
a(12h)^2 + h = 3/2
a(42h)^2 + h = 3
solve to get
x = 1/18 (y7)^2 + 7/2
x = 1/2 (y2)^2 + 1 👍
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answered by oobleck
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