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A ship leaves port and travels 21km on a bearing of 032 degrees and then 45km on a bearing of 287 degrees. A. calculate it distance from the port. B. calculate the bearing of the port from the ship

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2 answers

  1. 21km on a HEADING of 032 degrees
    distance north = 21 cos 32 = 17.8
    distance West = -21 sin 32 (really east so negative) = -11.1

    45km on a HEADING of 287 degrees (73 deg west of north)
    distance north = 45 cos 73 = 13.2
    distance west = 45 sin73 = 43.0

    total north = 31
    total west = 31.9

    distance =sqrt (31^2 + 31.9^2) = 44.5
    tan angle west of north = 31.9/31 = 1.03
    so angle w of n = 45.8
    360 - 45.8 = 314 deg bearing from start

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  2. 314 - 180 = 134 is bearing of port from ship then

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