Which of the following expressions have a value of −3–√?

sin(11π/6)
cos(5π/3)
cot(7π/6)
tan(11π/6)
cot(2π/3)
sin(5π/3)
csc(5π/3)
cos(7π/6)
cos(π/6)
csc(2π/3)

I think none..but that is not an option...so do I go with cot(7π/6)

thanks

no idea what "−3–√" means

tan π/6 = cot π/3 = 1/√3
cot π/6 = tan π/3 = √3
so,
tan 11π/6 = -1/√3
cot 7π/6 = √3
and so on. Draw the angles in the proper quadrant to see.
tanθ = y/x
cotθ = x/y

sorry Oobleck

It's supposed to be −√3