suppose a ball is thrown straight up into the air, and the height of the ball above the ground is given by the function h(t) = 6 + 37t  16t^2, where h is in feet and t is in seconds. At what time t does the ball stop going up and start returning to earth?
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1 answer

when dh/dt = 0
dh/dt = 37 32 t
t = 37/32 👍
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answered by Anonymous
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