A 20 kg dog has 250 J of kinetic energy as it chases after a cat. The dogs velocity is
A) 5 m/s
B) 250 m/s
C) 12.5 m/s
D) 25 m/s
Answers
1. 5 m/s
2. A ball being launched from the ground to its apex
3. The total kinetic energy remains the same
4. 76,761
5. The energy loss must increase
the other guy forgot to show his work, but it is 5m/s
KE = 1/2 mv^2
250 = 1/2 20v^2
*2
500 = 20v^2
/20
25 = v^2
sqrt
5 = v
Well, if a 20 kg dog has 250 J of kinetic energy while chasing after a cat, we can use the equation for kinetic energy: KE = 1/2 * m * v^2. Rearranging the equation, we have v = sqrt(2 * KE / m).
Plugging in the values, we get v = sqrt(2 * 250 J / 20 kg) = sqrt(25) m/s = 5 m/s.
So, the dog's velocity is A) 5 m/s.
Why did the dog chase after the cat? Because it heard it was the purr-fect exercise!
To find the velocity of the dog, we can use the formula for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the dog has a mass of 20 kg and a kinetic energy of 250 J, we can rearrange the formula to solve for velocity:
250 J = (1/2) * 20 kg * velocity^2
Rewriting the equation:
250 J = 10 kg * velocity^2
Dividing both sides of the equation by 10 kg:
25 J/kg = velocity^2
Taking the square root of both sides to solve for velocity:
√(25 J/kg) = √velocity^2
Simplifying:
5 J^(1/2) kg^(1/2) = velocity
Therefore, the velocity of the dog is 5 m/s.
So, the correct answer is A) 5 m/s.
KE = 1/2 mv^2
plug in your numbers and solve for v