log base 2 log base 2 log base 3 27 to the power 3
Without some kind of brackets to establish an order of operation, this
is too ambiguous.
e.g. are they "nested" logs ?
since 27 = 3^3 you have 27^3 = 3^9
log3(3^9) = 9
so you are left with
log2 log2 9
Not much you can do with that except evaluate it.
log29 = 3.1699
log2 3.1699 = 1.6644
the answer is five this was sooo easy for me i cnt belive u couldnt dothis bc i tq was sod soo esY FOR ME...
To calculate the value of log base 2 log base 2 log base 3 27^3, we need to break down the equation step by step.
Step 1: Calculate log base 3 of 27
To find log base 3 of 27, we can use the formula log(base b) x = log(x) / log(b). In this case, b is 3 and x is 27.
log base 3 (27) = log (27) / log (3)
= 3 / log (3)
Step 2: Calculate log base 2 of log base 3 of 27
Now that we have found log base 3 of 27, we can use it to calculate log base 2 of that value. Let's call log base 3 of 27 as y.
log base 2 (y) = log (y) / log (2)
Substituting the value of y from step 1:
log base 2 (log base 3 (27)) = log (3 / log (3)) / log (2)
Step 3: Calculate log base 2 of log base 2 of log base 3 of 27
Finally, we can calculate log base 2 of the value obtained in step 2, which is log base 3 of 27.
log base 2 (log base 2 (log base 3 (27))) = log (log (3 / log (3)) / log (2)) / log (2)
Simplifying this equation can be quite complex. However, plugging this expression into a scientific calculator or using a computer algebra system will give you the numerical answer.
Note: Since the expression involves multiple logarithms, it can be challenging to calculate the value without the aid of a calculator or software program.