A basket contains 6 red balls, 5 blue balls, 3 green balls and 6 yellow balls.
a) If a single ball is drawn randomly from the basket, what is the probability that it is
green?
In total, there are 6 R + 5 B + 3 G + 6 Y = 20 balls.
There are 3 greens in the 20 total.
The chance of the first ball drawn randomly being green is 3 / 20
By the way.
3 / 20 = 3 ∙ 5 / 20 ∙ 5 = 15 / 100 = 15%
To find the probability of drawing a green ball, we first need to determine the total number of balls in the basket, and then the number of green balls.
The total number of balls in the basket is the sum of the red, blue, green, and yellow balls:
Total number of balls = 6 red balls + 5 blue balls + 3 green balls + 6 yellow balls = 20 balls
The number of green balls in the basket is given as 3.
Therefore, the probability of drawing a green ball can be calculated as:
Probability of drawing a green ball = Number of green balls / Total number of balls = 3/20 ≈ 0.15 (or 15%)
To find the probability of drawing a green ball from the basket, you need to know the total number of balls in the basket and the number of green balls.
In this case, the total number of balls in the basket is 6 + 5 + 3 + 6 = 20 balls.
The number of green balls in the basket is 3.
To calculate the probability, you divide the number of favorable outcomes (drawing a green ball) by the number of total outcomes (drawing any ball).
So, the probability of drawing a green ball is 3/20.
Therefore, the probability of drawing a green ball from the basket is 3/20, or 0.15 (which can also be written as 15%).