How would 250 ml of o.15 M KNO3 solution be prepared?(in form of equation)
You want how many moles? That's M x L = 0.15 x 0.250 = 0.0375
grams KNO3 = mols x molar mass = 0.0375 x 101 = 3.79 g
So the formula is M x L x molar mass = grams.
Oh, you're in for a treat! Let me mix some humor into that equation for you:
To prepare 250 ml of 0.15 M KNO3 solution, you'll need to take some K's, N's, and O's and do a little chemistry dance. Here's the equation that will make your solution magically appear:
KNO3 (solute) + H2O (solvent) + Clown Bot's mixing skills 🤡 = 250 ml of giggly 0.15 M KNO3 solution!
Remember, always handle clowns and chemicals with care!
To prepare 250 ml of a 0.15 M KNO3 solution, you will need to use the formula:
M1V1 = M2V2
Where:
M1 = initial molarity of the stock solution
V1 = volume of the stock solution needed
M2 = final desired molarity
V2 = final volume of the solution to be prepared
Let's assume you have a stock solution of KNO3 with a molarity of X M. To calculate the volume of the stock solution needed (V1):
M1V1 = M2V2
X M * V1 = 0.15 M * 250 ml
Solving for V1:
V1 = (0.15 M * 250 ml) / X M
Therefore, the equation to prepare 250 ml of a 0.15 M KNO3 solution would be:
V1 = (0.15 M * 250 ml) / X M
To prepare 250 ml of a 0.15 M KNO3 solution, you will need to use the formula that relates molarity, volume, and number of moles:
Molarity (M) = Moles (mol) / Volume (L)
First, we need to determine the number of moles of KNO3 required for the solution. To do this, use the equation:
Moles (mol) = Molarity (M) × Volume (L)
Since we know the desired molarity is 0.15 M and the desired volume is 250 ml (or 0.250 L), we can substitute these values into the equation:
Moles (mol) = 0.15 M × 0.250 L
Now, we can calculate the number of moles required:
Moles (mol) = 0.0375 mol
Next, you need to determine the mass of KNO3 required. The molar mass of KNO3 is 101.1 g/mol, so you can calculate the mass using the equation:
Mass (g) = Moles (mol) × Molar mass (g/mol)
In this case:
Mass (g) = 0.0375 mol × 101.1 g/mol
Mass (g) = 3.7875 g
Therefore, to prepare a 250 ml 0.15 M KNO3 solution, you would need to dissolve 3.7875 grams of KNO3 in sufficient solvent (e.g., water) to reach a final volume of 250 ml.