In each of three trials of an investigation, a single force is applied to a mobile. Each time, the mobile acquires a different acceleration. The table shows the relationship between the acceleration and the acting force.
Force (N) Acceleration (m/s^2)
1.2 4.8
0.7 2.8
1.6 6.4
Which phrase best describes a graph that would represent the relationship shown in the table?
A) an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
B) an upward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
C) a downward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
D) a downward-sloping line drawn on a graph with acceleration shown on the x-axis and force shown on the y-axis
1. A nonzero net force is acting on it.
2. an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis.
3. Graphs visually show the relationship between the variables under investigation.
4. The object is at rest.
5. The cart will move to the right.
(Q1) What is the measure of the amount of matter in an object?
(C) mass
(Q2) How much force in Newtons is required to accelerate a 5 kg bowling ball at 2 m/s2?
(A) 10N
(Q3) Which statement correctly applies to a car that changes its velocity over a period of time?
(D) A nonzero net force is acting on it.
(Q4) In each of three trials of an investigation, a single force is applied to a mobile. Each time, the mobile acquires a different acceleration. The table shows the relationship between the acceleration and the acting force.
(C) an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis
(Q5) Which statement describes the motion of an object when the net force is zero?
(D) The object is at rest.
(Newton's Second Law Quick Check 2022/2023 school year.)
its "an upward-sloping line drawn on a graph with acceleration shown on the y-axis and force shown on the x-axis"
Sorry the force is: 1.2, 0.7, and 1.6
and the acceleration is: 4.8, 2.8, and 6.4
but whats the answer??
F = m a
F = (1/4) a
or
a = 4 F
mass = 0.25
the way you phrased it was acceleration = slope (which is 4) * force
so force is x axis and resulting acceleration (dependent variable) is y axis