Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Find the image vertices for a dilation with center
(
0
,
0
)
and a scale factor of 4.
Quadrilateral with vertices at A left parenthesis negative 3 comma 1 right parenthesis, B left parenthesis 4 comma negative 3 right parenthesis, C left parenthesis 2 comma 3 right parenthesis, D left parenthesis negative 1 comma 4 right parenthesis.
i need help
first, you need help just typing things so they can be easily read. Why not just say
Find the image vertices for a dilation with center (0,0) and a scale factor of 4.
Quadrilateral ABCD with vertices at
A(-3,1), B(4,-3), C(2,3), D(-1,4).
Much easier to read, and in any case, all you have to do is multiply each coordinate by the scale factor of 4.
soooo. you mean like -3 times 4 and 1 times four would be the coordinates for A??? as it would be A(-12,4)
Bro this is what im talking about, read my other post. Stop being rude. @oobleck if your going to be rude to innocent people then just stop helping its so easy not to be a freaking a-hole all the time.
PLEASE HURRY I NEED HELP LMAO
To find the image vertices after a dilation with a scale factor of 4 and center at (0,0), we need to multiply the coordinates of each vertex by the scale factor.
Given the coordinates of the original quadrilateral:
A (-3, 1)
B (4, -3)
C (2, 3)
D (-1, 4)
For the dilation with a scale factor of 4 and center (0,0), we will multiply the x and y coordinates of each vertex by 4.
For vertex A:
New x-coordinate = -3 * 4 = -12
New y-coordinate = 1 * 4 = 4
So, the image vertex A' = (-12, 4)
For vertex B:
New x-coordinate = 4 * 4 = 16
New y-coordinate = -3 * 4 = -12
So, the image vertex B' = (16, -12)
For vertex C:
New x-coordinate = 2 * 4 = 8
New y-coordinate = 3 * 4 = 12
So, the image vertex C' = (8, 12)
For vertex D:
New x-coordinate = -1 * 4 = -4
New y-coordinate = 4 * 4 = 16
So, the image vertex D' = (-4, 16)
Therefore, the image vertices for the dilation with center (0,0) and scale factor of 4 are:
A' (-12, 4)
B' (16, -12)
C' (8, 12)
D' (-4, 16)