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Find the image vertices for a dilation with center
(
0
,
0
)
and a scale factor of 4.
Quadrilateral with vertices at A left parenthesis negative 3 comma 1 right parenthesis, B left parenthesis 4 comma negative 3 right parenthesis, C left parenthesis 2 comma 3 right parenthesis, D left parenthesis negative 1 comma 4 right parenthesis.
answer the quistion
how are you ganna say answer it when you didnt
Quadrilateral with vertices at A left parenthesis negative 3 comma 1 right parenthesis, B left parenthesis 4 comma negative 3 right parenthesis, C left parenthesis 2 comma 3 right parenthesis, D left parenthesis negative 1 comma 4 right parenthesis.
Geessh, how about this:
Quadrilateral with vertices at A(-3, 1), B(4,-3), C(2,3), D(-1,4)
Now what about it???
If you still want to apply a scale factor of 4 to this, just multiply each number you see by 4
I need help im from connexus and im on points lines and triangles quiz part 2 and i got 2 questions
To find the image vertices of a dilation with a scale factor of 4 and a center at (0, 0), we need to multiply the coordinates of each vertex by the scale factor.
Given a quadrilateral with vertices A(-3, 1), B(4, -3), C(2, 3), and D(-1, 4), we can find the image vertices as follows:
1. For vertex A(-3, 1):
Multiply each coordinate by the scale factor (4): A' = (4 * -3, 4 * 1)
Simplifying, we get A' = (-12, 4)
2. For vertex B(4, -3):
Multiply each coordinate by the scale factor (4): B' = (4 * 4, 4 * -3)
Simplifying, we get B' = (16, -12)
3. For vertex C(2, 3):
Multiply each coordinate by the scale factor (4): C' = (4 * 2, 4 * 3)
Simplifying, we get C' = (8, 12)
4. For vertex D(-1, 4):
Multiply each coordinate by the scale factor (4): D' = (4 * -1, 4 * 4)
Simplifying, we get D' = (-4, 16)
Therefore, the image vertices of the given quadrilateral under the given dilation are:
A'(-12, 4), B'(16, -12), C'(8, 12), and D'(-4, 16).