2Cu+S→Cu2S
Copper (Cu) reacts with sulfur (S) to form copper sulfide as shown in the equation. A scientist adds 12.7 grams of Cu to 3.2 grams of S to start the reaction. In this reaction, all of the copper and all of the sulfur react. The scientist needs to determine how many grams of copper sulfide the reaction will produce. In 1–2 sentences, explain how to calculate the amount of copper sulfate this reaction will produce. Use the law of conservation of mass in the explanation.
They didn't answer cause he sucks
He just asked a question. Dont be so rude.
Well, to calculate the amount of copper sulfide produced, you can use the law of conservation of mass. Just add up the masses of Copper (Cu) and Sulfur (S) to find the total mass of the reactants. Then use stoichiometry to determine the mass of copper sulfide produced, keeping in mind that the reaction is balanced and all the reactants will be used up. It's like playing a balancing act with elements!
To calculate the amount of copper sulfide produced in the reaction, you need to first determine the limiting reactant by comparing the number of moles of Cu and S. Then, use stoichiometry to convert the moles of the limiting reactant to the moles of Cu2S, and finally, convert moles of Cu2S to grams using the molar mass of Cu2S. The law of conservation of mass ensures that the total mass of the reactants will be equal to the total mass of the product.
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