A machine’s efficiency is determined to be 60%. The input work is 3,000 joules. What is the output work?
A) 180,000 joules
B) 50 joules
C) 1,800 joules
D) 5,000 joules
Plz Helpppp!!!!
Q1. A machine’s efficiency is determined to be 60%. The input work is 3,000 joules. What is the output work?
A1. 1,800 joules
Q. A gardener uses a wheelbarrow as a lever to lift some dirt. The energy applied by the gardener is 2,000 joules. The efficiency of the work done is 95%. How much work is done on the dirt?
A2. 1,900 joules
Q3. A pulley system is operating at only 50% efficiency. How could the efficiency be increased?
A3. by reducing the friction on the pulleys
Q4. What is the name of the fixed point about which a lever rotates?
A4. fulcrum
Q5. Which car has the greatest efficiency?
A5. a 1,200 kg car that travels 20 km per liter of fuel
I just took the Efficiency of Machines Quick Check for Unit 2 Lesson 5 of my Science class, and these are 100% correct, I promise.
@Anonymous thx i got 100% ^^ <3
0.60 * 3000 = ____
Anonymous is still right
Well, since we're talking about efficiency, let's do a little efficiency math, shall we?
Efficiency = (Output Work / Input Work) * 100
We know the efficiency is 60%, or 0.6. And the input work is 3,000 joules. So let's solve for the output work:
0.6 = (Output Work / 3,000) * 100
Now let's do some cross multiplying and divide by 100:
0.6 * 3,000 = Output Work
Okay, let me do the math... *calculating noises*
It seems the output work is 1,800 joules. So the answer is C) 1,800 joules.
You did it! Feel free to celebrate with a little efficiency dance. Just be careful not to trip over your own energy!
To find the output work of a machine, we can use the formula for efficiency:
Efficiency = (Output work / Input work) x 100%
In this case, the efficiency of the machine is given as 60% (which can be written as 0.60 in decimal form) and the input work is 3,000 joules. Let's call the output work "O".
0.60 = (O / 3,000) x 100%
To solve for O, we can rearrange the equation:
O = (0.60 x 3,000) / 100
Simplifying the expression:
O = 1,800 joules
Therefore, the output work of the machine is 1,800 joules. So, the answer is C) 1,800 joules.