Compared to the annual rainfall from 1981-2008, the 309.36 mm of rainfall in Getafe, Spain (near Madrid) in 2009 was more than 42.07% of the previous 28 years, but the 463.04 mm of rainfall in 2010 was more rainfall than 91.92% of those years.
A-Calculate the amount of rainfall needed in 2011 season to maintain the average established from 1981-2008.
B-Getafe received 293.08 mm of rain in 2011. Calculate the percentile to accurately complete the statement below:
2011 saw more rainfall than ______% of the years from 1981-2008.
C- Find the average annual rainfall from 1981 to 2011 to the nearest hundredth of a millimeter.
A) Well, if the 309.36 mm of rainfall in 2009 was more than 42.07% of the previous 28 years, then you can calculate the average rainfall from 1981-2008 by dividing 309.36 mm by 0.4207. So, 309.36 mm / 0.4207 ≈ 735.14 mm. Therefore, to maintain the average established from 1981-2008, the amount of rainfall needed in the 2011 season would be approximately 735.14 mm.
B) Getafe received 293.08 mm of rain in 2011. Now, let's find out how many years from 1981-2008 had less rainfall than that. Multiply 293.08 mm by 0.9192, and you get 269.32 mm. Therefore, 2011 saw more rainfall than approximately 91.92% of the years from 1981-2008.
C) To find the average annual rainfall from 1981 to 2011, you need to add up the rainfall from each year and divide by the total number of years (31 in this case). So, add up the rainfall from 1981-2011, which is 735.14 mm + 463.04 mm + 293.08 mm, and then divide by 31. That gives you an average annual rainfall of approximately 609.84 mm to the nearest hundredth.
A- To calculate the amount of rainfall needed in 2011 to maintain the average established from 1981-2008, we need to find the average annual rainfall for the previous 28 years.
First, calculate the total rainfall from 1981 to 2008:
Total rainfall from 1981-2008 = 309.36 mm (2009) + 463.04 mm (2010) = 772.4 mm
Next, calculate the average annual rainfall for the previous 28 years:
Average rainfall from 1981-2008 = 772.4 mm / 28 years = 27.5857 mm/year (rounded to four decimal places)
Therefore, the amount of rainfall needed in 2011 to maintain the average established from 1981-2008 is approximately 27.59 mm.
B- To calculate the percentile for the rainfall in 2011, we need to compare it to the rainfall from 1981-2008.
First, calculate the total rainfall from 1981 to 2011:
Total rainfall from 1981-2011 = 772.4 mm (1981-2008) + 293.08 mm (2011) = 1065.48 mm
Next, calculate the percentage of years from 1981-2008 that had less rainfall than 2011:
Percentage = (Number of years with less rainfall / Total number of years) x 100
Percentage = (28 years with less rainfall / 29 total years) x 100 = 96.55%
Therefore, 2011 saw more rainfall than 96.55% of the years from 1981-2008.
C- To find the average annual rainfall from 1981 to 2011, including 2011, we need to calculate the total rainfall for the 31 years.
Total rainfall from 1981-2011 = 772.4 mm (1981-2008) + 293.08 mm (2011) = 1065.48 mm
Next, calculate the average annual rainfall for the 31 years:
Average rainfall from 1981-2011 = 1065.48 mm / 31 years = 34.3703 mm/year (rounded to four decimal places)
Therefore, the average annual rainfall from 1981 to 2011 is approximately 34.37 mm.
A- To calculate the amount of rainfall needed in the 2011 season to maintain the average established from 1981-2008, we need to find the average rainfall for those 28 years.
The total rainfall for the 28 years is given as 309.36 mm for 2009 and 463.04 mm for 2010.
So, the total rainfall for the 1981-2008 period is (28 * average rainfall) - 309.36 - 463.04.
To find the average rainfall, we divide the total rainfall for the 1981-2008 period by 28.
B- To calculate the percentile of the 293.08 mm of rain received in Getafe in 2011, we need to compare it with the rainfall from 1981-2008 and see how it ranks among those years.
We can do this by finding the number of years out of 28 that receive less rainfall than 293.08 mm, and then dividing that number by 28 and multiplying by 100 to get the percentile.
C- To find the average annual rainfall from 1981 to 2011, we need to add up the rainfall for each year and then divide by the number of years (31).
We can use the given values for 2009, 2010, and 2011, and assume the average rainfall for the other years is the same as the average established from 1981-2008.
To find the average, add up the total rainfall from 1981-2008, the rainfall in 2009, 2010, and 2011, and then divide by 31.