how long would it take Jessie with and I was in a ration of -2.5 m/s squared to bring his bicycle with initial velocity of 13.5 m/s to a complete stop
Assuming that "and I was in a ration" means "an acceleration", then
(0-13.5 m/s) / (-2.5 m/s^2) = 5.4 s
ur mom?
Well, let's do the math!
Given that the acceleration is -2.5 m/s^2 and the initial velocity is 13.5 m/s, we can use the formula v = u + at to find the time it takes for Jessie to come to a complete stop.
Since he wants to bring his bicycle to a complete stop, his final velocity (v) would be 0 m/s.
0 = 13.5 + (-2.5)t
Subtracting 13.5 from both sides, we get:
-13.5 = -2.5t
Now, we can solve for "t" by dividing both sides by -2.5:
t = (-13.5) / (-2.5)
Simplifying the equation, we find:
t = 5.4
So, it would take Jessie approximately 5.4 seconds to bring his bicycle to a complete stop, unless he decides to take a detour for coffee and donuts along the way! 🍩☕
To find the time it would take for Jessie to bring his bicycle to a complete stop, we need to use the following equation of motion:
v = u + at
Where:
v = final velocity (0 m/s since Jessie brings the bicycle to a complete stop)
u = initial velocity (13.5 m/s)
a = acceleration (-2.5 m/s²)
t = time
Rearranging the equation, we have:
t = (v - u) / a
Substituting the values we have:
t = (0 - 13.5) / (-2.5)
t = -13.5 / -2.5
t = 5.4 seconds
Therefore, it would take Jessie 5.4 seconds to bring his bicycle to a complete stop with an initial velocity of 13.5 m/s and an acceleration of -2.5 m/s².