24 g of carbon and 32 g of oxygen combine to form carbon monoxide. What is the mass of the carbon monoxide formed?
oops!! not 28 g.
2C + O2 ==> 2CO
mols C = g/atomic mass = 24/12 = 2
mols Oxygen = 32/32 = 1 mol O2
2 mols C will give 2 mols CO = 2*28 = 56 g CO OR
1 mol O2 will give 2 mols CO = 56 g CO Or to use the Law of conservatiion of matter this is
24 + 32 = 56 to start so 56 for the product total.
Well, let's do some math but with a humorous twist! Carbon and oxygen had a little date and decided to get together to form carbon monoxide. So, we have 24 grams of carbon and 32 grams of oxygen. Now, let's imagine a nice wedding ceremony where carbon and oxygen say "I do" and become carbon monoxide.
Carbon, being a bit of a lightweight, only weighs 24 grams, while oxygen, on the other hand, weighs a hefty 32 grams. But in a loving relationship, it's all about balance, so they combine their masses to form carbon monoxide. In this case, the carbon brought 24 grams to the table, and the oxygen brought 32 grams.
Now, if we add those up, we get 24 + 32 = 56 grams of carbon monoxide. Ta-da! That's how much carbon monoxide was formed at the wedding of carbon and oxygen. They truly make a gassy couple!
To calculate the mass of carbon monoxide formed, we need to consider the law of conservation of mass. This law states that in a chemical reaction, the total mass of the reactants equals the total mass of the products.
Given that 24 g of carbon and 32 g of oxygen combine to form carbon monoxide, we can assume that the reaction is as follows:
C + O₂ → CO
The molar mass of carbon (C) is 12.01 g/mol, the molar mass of oxygen (O₂) is 32.00 g/mol, and the molar mass of carbon monoxide (CO) is 28.01 g/mol.
We can calculate the number of moles for each element in the reaction:
Number of moles of carbon (C) = Mass of carbon / Molar mass of carbon
= 24 g / 12.01 g/mol
= 1.998 mol (approximately)
Number of moles of oxygen (O₂) = Mass of oxygen / Molar mass of oxygen
= 32 g / 32.00 g/mol
= 1.000 mol (approximately)
Since the balanced equation shows that the coefficients of carbon (C) and carbon monoxide (CO) are both 1, we can conclude that the number of moles of CO formed is also 1.000 mol.
Finally, we can calculate the mass of carbon monoxide:
Mass of carbon monoxide (CO) = Number of moles of CO × Molar mass of CO
= 1.000 mol × 28.01 g/mol
= 28.01 g
Therefore, the mass of carbon monoxide formed in this reaction is 28.01 grams.
To find the mass of carbon monoxide formed, we need to calculate the total mass of carbon and oxygen before they combine, and then subtract the mass of carbon and oxygen that remains after the reaction.
1. First, let's calculate the molar mass of carbon (C) and oxygen (O) using the periodic table. The atomic mass of carbon is approximately 12 g/mol, and oxygen is approximately 16 g/mol.
2. Now, calculate the number of moles for each element using the given masses.
Number of moles of carbon = Mass of carbon / Molar mass of carbon
Number of moles of carbon = 24 g / 12 g/mol
Number of moles of carbon = 2 moles
Number of moles of oxygen = Mass of oxygen / Molar mass of oxygen
Number of moles of oxygen = 32 g / 16 g/mol
Number of moles of oxygen = 2 moles
3. The balanced chemical equation for the formation of carbon monoxide is:
C + O2 -> CO
According to the equation, the reaction consumes 1 mole of carbon and 1 mole of oxygen to form 1 mole of carbon monoxide.
Since we have equal amounts of carbon and oxygen, we know that the limiting reactant is the one with fewer moles, which is carbon in this case.
4. Therefore, the reaction will consume 1 mole of carbon and 1 mole of oxygen.
5. Calculate the molar mass of carbon monoxide (CO). The atomic mass of carbon is 12 g/mol, and oxygen is 16 g/mol.
Molar mass of carbon monoxide = Atomic mass of carbon + Atomic mass of oxygen
Molar mass of carbon monoxide = 12 g/mol + 16 g/mol
Molar mass of carbon monoxide = 28 g/mol
6. Calculate the mass of carbon monoxide formed using the molar mass and the number of moles of carbon monoxide.
Mass of carbon monoxide = Number of moles of carbon monoxide * Molar mass of carbon monoxide
Mass of carbon monoxide = 1 mole * 28 g/mol
Mass of carbon monoxide = 28 g
Therefore, the mass of carbon monoxide formed is 28 grams.
C = 12 grams / mol
O = 16 grams / mol
so 24 grams of C is 2 mols
and 32 grams of O is 2 mols of O and 1 mol of O2
2C + O2 --->2CO
so you get 12 + 16 = 28 grams