Multiply and Divide Integers Quiz Part 1
1. What is the value of 14 – a2 given a = –3? (1 point)
23
11
8
5
2. Which equation represents “fifteen more than r is sixty-one?” (1 point)
r + 61 = 15
r + 15 = 61
r – 15 = 61
r – 61 = 15
3. What is the value of 42 – 2(3 • 5 + 1)? (1 point)
8
1
–16
–21
4. What symbol is needed between –2 ? |–3| to make a true statement? (1 point)
<
>
=
5. What is the value of 7(10 – 23) + 8 ÷ 2? (1 point)
11
13
18
32
6. Which set of integers are in the right order from least to greatest? (1 point)
|–10|, –3, 2, 7
7, |–10|, –3, 2
2, –3, 7, |–10|
–3, 2, 7, |–10
7. What is the additive inverse of –42? (1 point)
–42
42
–(–(–42))
–|–42|
8. What is the solution to 107 – (–25)? (1 point)
132
82
–82
–132
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Hey bot, can you help me with this problem?
x=6y−3
2x+7y=13(1 point)
To solve this system of equations, you can substitute x in terms of y from the first equation into the second equation, then solve for y:
x = 6y - 3
2x + 7y = 13
2(6y - 3) + 7y = 13 (substitute x = 6y - 3 into second equation)
12y - 6 + 7y = 13 (distribute the 2)
19y = 19 (combine like terms)
y = 1
Now that you have the value of y, you can substitute it back into the first equation to solve for x:
x = 6y - 3
x = 6(1) - 3
x = 3
Therefore, the solution to the system of equations is (x, y) = (3, 1).
how about this one?
8x−3y= −22
y=10+4x
To solve this system of equations, you can substitute y in terms of x from the second equation into the first equation, then solve for x:
8x - 3y = -22
y = 10 + 4x
8x - 3(10 + 4x) = -22 (substitute y = 10 + 4x into the first equation)
8x - 30 - 12x = -22 (distribute the -3)
-4x - 30 = -22 (combine like terms)
-4x = 8 (add 30 to both sides)
x = -2
Now that you have the value of x, you can substitute it back into the second equation to solve for y:
y = 10 + 4x
y = 10 + 4(-2)
y = 2
Therefore, the solution to the system of equations is (x, y) = (-2, 2).
5x+2y=14
x−6y=22
To solve this system of equations, you can use the elimination method. Multiply the second equation by 5 and add it to the first equation to eliminate x:
5x + 2y = 14
5(x - 6y) = 5(22)
5x - 30y = 110
Now add the first equation to the result:
5x + 2y = 14
+ (5x - 30y = 110)
-----------------
10x - 28y = 124
Divide both sides by 2:
5x - 14y = 62
Now solve for x in terms of y using the second equation:
x - 6y = 22
x = 6y + 22
Substitute for x in the previous equation:
5(6y + 22) - 14y = 62
30y + 110 - 14y = 62
16y = -48
y = -3
Substitute this value back into the second equation:
x - 6y = 22
x - 6(-3) = 22
x + 18 = 22
x = 4
Therefore, the solution to the system of equations is (x, y) = (4, -3).
–9x+y=12
2x+4y= −28