1. 62 is divisible by which of the following numbers?

A. 1, 3, 31, 62
B. 1, 2, 3, 31
C. 1, 4, 16, 62
D. 1, 2, 31, 62

2. 45 is divisible by which of the following numbers/
A. 1, 5 8
B. 1, 2, 3
C. 1, 2 ,5
D. 1, 3, 5, 9

3. Which of the following numbers is divisible by 2, 3, 5, 6, 9, and 10?
A. 420
B. 540
C. 250
D. 510

4. Which number is divisible by 2, 9, and 10?
A. 45
B. 60
C. 90
D. 150

can someone please help me with these questions? And i'm in 6th grade.

Good morning @HI

i will grade give me 1 sec

seriously? i told you my answers and your not replying..

someone please help me :| the asnwer i think they are is a, c, b, and a

okay! ty

uhm.. the answer that i picked and you said they were correct.. but when i submit it i got a 25%.. uhm thanks a lot.. :|

Of course! I'd be happy to help you with these questions.

1. To find out if 62 is divisible by a certain number, you need to check if 62 can be divided evenly by that number without leaving a remainder. Let's check the options one by one:
- Option A: Is 62 divisible by 1? Yes, because any number is divisible by 1.
- Option B: Is 62 divisible by 2? No, because 62 divided by 2 is 31 with no remainder.
- Option C: Is 62 divisible by 4? No, because 62 divided by 4 is 15 with a remainder of 2.
- Option D: Is 62 divisible by 31? Yes, because 62 divided by 31 is 2 with no remainder.

Based on this, the correct answer is Option A: 1, 3, 31, and 62 are the numbers by which 62 is divisible.

2. Let's follow the same process for this question:
- Option A: Is 45 divisible by 1? Yes.
- Option B: Is 45 divisible by 2? No.
- Option C: Is 45 divisible by 5? Yes, because 45 divided by 5 is 9 with no remainder.
- Option D: Is 45 divisible by 3? Yes, because 45 divided by 3 is 15 with no remainder.

Based on this, the correct answer is Option D: 1, 3, 5, and 9 are the numbers by which 45 is divisible.

3. To find a number that is divisible by 2, 3, 5, 6, 9, and 10, we need to find the least common multiple (LCM) of these numbers. The LCM is the smallest number that is divisible by all the given numbers.
- Let's find the LCM of 2, 3, 5, 6, 9, and 10:
- Prime factorize each number: 2 = 2, 3 = 3, 5 = 5, 6 = 2 × 3, 9 = 3 × 3, 10 = 2 × 5.
- Take the maximum power of each prime factor: 2² × 3² × 5 = 4 × 9 × 5 = 180.
- Therefore, the LCM of these numbers is 180.

Out of the given options, the number 540 is divisible by 2, 3, 5, 6, 9, and 10. Therefore, the correct answer is Option B: 540.

4. Similar to the previous question, we need to find the LCM of 2, 9, and 10.
- Prime factorize each number: 2 = 2, 9 = 3 × 3, 10 = 2 × 5.
- Take the maximum power of each prime factor: 2 × 3² × 5 = 2 × 9 × 5 = 90.

Out of the given options, the number 90 is divisible by 2, 9, and 10. Therefore, the correct answer is Option C: 90.

I hope this explanation helps you understand how to figure out if a number is divisible by certain other numbers. If you have any further questions, feel free to ask!

my choices are a, c, b and a

I'm pretty sure they are correct try them

ps there right you should try to do it bye yourself and ask for what you need help on and ask for what you need not for the awencers or when you go back to public school youll fail

well Your Welcome it is not my fault you where wrong remember yesterday when i got you a 100% well im going to be around to help but not you

you are needy and your going to fail at life cause you just bege for answers all your life it is sad how you cant do anything yourself your just a leach you is on this website not for help for answers if i did that my whole life id have more enemies than i have now im 14 on here trying to help and geet help your looking for answers do the work your self for once

We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.

What are your choices?