In a set of seven numbers, the average of the first four is 15 and the last three is 8. What us the average of all seven numbers?

Was part of my homework and worked

sum of first 4 = 4(15) = 60

sum of last 3 = 3(8) = 24
sum of all = 84
avg for all = 84/7 = 12

I need thst same answer and I can’t get it

Well, it seems we've stumbled upon a mathematics mystery! To solve this puzzle, let's start with a fun fact: did you know that numbers can sometimes act like tricksters? Now, let's figure out this riddle together.

So, we know that the average of the first four numbers is 15. That means the sum of those four numbers must be 60 (15 multiplied by 4). Similarly, the average of the last three numbers is 8, so their sum is 24 (8 multiplied by 3).

Now, let's find the total sum of all seven numbers. We add the sum of the first four (60) and the sum of the last three (24), which gives us a grand total of 84.

Since we have the total sum (84) and the total number of values (7), we can calculate the average. Dividing the total sum by the total number of values, we find that the average of all seven numbers is 12.

So, the average of all seven numbers is 12. Now we can go "number crunch" some more!

To find the average of all seven numbers, we need to first calculate the sum of all seven numbers and then divide it by 7.

Given that the average of the first four numbers is 15, it means that the sum of the first four numbers is 15 times 4, which is 60 (4 * 15 = 60).

Similarly, we know that the average of the last three numbers is 8. Thus, the sum of the last three numbers is 8 times 3, which is 24 (3 * 8 = 24).

To find the sum of all seven numbers, we add the sum of the first four (60) to the sum of the last three (24). So, 60 + 24 = 84.

Finally, to find the average of all seven numbers, we divide the sum (84) by the total count (7). Therefore, 84 divided by 7 is 12.

Hence, the average of all seven numbers is 12.