You place a piece of paper on a balance and find that its mass is 0.63 g. You add a lump of NaOH to the paper and get a mass of 22.21 g. How Much NaOH do you have on the balance, in grams, milligrams, micrograms and kilograms?
so I just subtract? How do I actually slove the problem? what am i suppose to do?
See my answer above to your repost. Oobleck did a great job. I have expanded on that answer above in which I've tried to draw a picture for you.
To find the mass of NaOH on the balance, you can subtract the mass of the paper from the total mass of the paper and NaOH.
First, let's find the mass of NaOH in grams:
Mass of NaOH = Total mass - Mass of paper = 22.21 g - 0.63 g = 21.58 g.
To convert grams to other units, we can use the following conversion factors:
1 gram (g) = 1000 milligrams (mg)
1 gram (g) = 1,000,000 micrograms (µg)
1 gram (g) = 0.001 kilograms (kg)
Now, let's convert the mass of NaOH to milligrams:
Mass of NaOH in milligrams = Mass of NaOH in grams × 1000 = 21.58 g × 1000 = 21580 mg.
To convert the mass of NaOH to micrograms:
Mass of NaOH in micrograms = Mass of NaOH in grams × 1,000,000 = 21.58 g × 1,000,000 = 21580000 µg.
To convert the mass of NaOH to kilograms:
Mass of NaOH in kilograms = Mass of NaOH in grams × 0.001 = 21.58 g × 0.001 = 0.02158 kg.
Therefore, the mass of NaOH on the balance is:
- 21.58 grams
- 21580 milligrams
- 21580000 micrograms
- 0.02158 kilograms.
22.21g - 0.63g = 21.58g
now do the other units