On takeoff a rocket accelerates from rest at a rate of 50m/s^2 for exactly 1 minute. The rockets speed after this minute of steady acceleration will be__m/s.
v = at
50 m/s^2 * 60s = 3000 m/s
Well, let me put on my rocket scientist hat for a moment. If the rocket is accelerating at a steady rate of 50m/s² for a whole minute, that's quite the "rocket-paced" acceleration!
To figure out the speed of the rocket after this minute of acceleration, we can use the formula:
speed = acceleration × time
In this case, the acceleration is 50m/s², and the time is 1 minute, which equals 60 seconds. Now let's put those values into the formula:
speed = 50m/s² × 60s
Doing some quick math:
speed = 3000m/s
So, after a minute of acceleration, the rocket's speed will be a "skyrocketing" 3000 meters per second! Hold onto your hats and enjoy the "out of this world" ride!
To find the speed of the rocket after 1 minute of steady acceleration, we can use the equation of motion:
v = u + at
Where:
v = final velocity (unknown)
u = initial velocity (0 m/s, as the rocket starts from rest)
a = acceleration (50 m/s^2)
t = time (1 minute = 60 seconds)
Plugging in the values:
v = 0 + (50 m/s^2)(60 s)
v = 0 + 3000 m/s
v = 3000 m/s
Therefore, the rocket's speed after 1 minute of steady acceleration will be 3000 m/s.
To find the speed of the rocket after 1 minute of acceleration, we can use the kinematic equation:
v = u + at
Where:
v = final velocity (speed)
u = initial velocity (resting speed, which is 0)
a = acceleration
t = time
Given:
u = 0 m/s (resting speed)
a = 50 m/s^2 (acceleration)
t = 1 minute = 60 seconds
Substituting the given values into the equation:
v = 0 + 50 * 60
Calculating this expression:
v = 0 + 3000
v = 3000 m/s
Therefore, the speed of the rocket after 1 minute of steady acceleration will be 3000 m/s.