Now wuttchica is 25 years old and he is older than his brother.in the next 15 years wuttilhai'S age will be two time of his brother's. How old is the brother at the present?

Let the brother's current age be x

in 15 years, the brother will be x+15 years old

In 15 years wutt... will be 40

40 = 2(x+15)
40 = 2x + 30
2x = 10
x = 5

finish with a conclusion statement.

W = Wuttchica's present age = 25

B = Brother's present age

After 15 years Wuttchica age will be

W + 15 = 25 + 15 = 40

Since after 15 years Wuttchica's will be two time of his brothers, after 15 years brother's age will be

40 / 2 = 20

Brother's present age = 20 - 15 = 5

To solve this problem, we'll need to set up some equations based on the information given.

Let's assume the brother's current age is x years. Since Wuttchica is older, their age difference will be x + y, where y is a positive integer (the age difference could be any positive whole number).

According to the problem, in the next 15 years, Wuttchica's age will be two times his brother's age. So, we can write the equation:

Wuttchica's age in (x + 15) = 2 * (brother's age in (x + 15)).

Now, let's solve the equation:

Wuttchica's age in (x + 15) = 2 * (brother's age in (x + 15))
25 + 15 = 2 * (x + 15)
40 = 2x + 30
2x = 40 - 30
2x = 10
x = 10 / 2
x = 5

Therefore, the brother is currently 5 years old.