Calculate the volume of concentrated nitric acid, 18 mol dm "-3" which is required to prepare 5.0 dm 3 of 2.0 mol dm "-3" nitric acid.
M1 V1 = M2 V2
so you just have to solve for v in
18v = 2.0*5.0
Calculate the volume of concentrated nitric acid, 18 moldm-³ which is required to prepare 5.0 dm-³ of 2.0 moldm-³ nitric acid
To calculate the volume of the concentrated nitric acid needed, you can use the formula:
C₁V₁ = C₂V₂
Where:
C₁ = Concentration of the concentrated nitric acid = 18 mol/dm³
V₁ = Volume of the concentrated nitric acid (what we need to find)
C₂ = Concentration of the desired nitric acid solution = 2.0 mol/dm³
V₂ = Required volume of the desired nitric acid solution = 5.0 dm³
Rearranging the formula to solve for V₁:
V₁ = (C₂ × V₂) / C₁
Substituting the given values:
V₁ = (2.0 mol/dm³ × 5.0 dm³) / 18 mol/dm³
Now, let's calculate the volume:
V₁ = (10 mol) / 18 mol/dm³
V₁ = 0.5556 dm³
Therefore, you would need approximately 0.5556 dm³ (or 555.6 mL) of concentrated nitric acid to prepare 5.0 dm³ of a 2.0 mol/dm³ nitric acid solution.
To calculate the volume of concentrated nitric acid needed to prepare the desired solution, you can use the concept of molarity (M) and the equation:
M1 × V1 = M2 × V2
Where:
M1 is the molarity of the concentrated nitric acid (18 mol/dm³)
V1 is the volume of the concentrated nitric acid (unknown)
M2 is the molarity of the desired nitric acid solution (2.0 mol/dm³)
V2 is the volume of the desired nitric acid solution (5.0 dm³)
Now, let's solve for V1:
V1 = (M2 × V2) / M1
Plugging in the values, we have:
V1 = (2.0 mol/dm³ × 5.0 dm³) / 18 mol/dm³
V1 = 0.5556 dm³
Therefore, you would need approximately 0.5556 dm³ (or 555.6 cm³ or 555.6 mL) of concentrated nitric acid with a molarity of 18 mol/dm³ to prepare 5.0 dm³ of a 2.0 mol/dm³ nitric acid solution.