determine three consecutive even integers, if the square of the largest integer less the square of the middle integer is 20 less than the square of the smallest integer
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1 answer

so, if the numbers are x2, x and x+2, we have
(x+2)^2  x^2 = (x2)^2  20
solve for x and you get 2,10
check:
12^2  10^2 = 8^2  20  yep
0^2  2^2 = (4)^2  20  yep 👍
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answered by oobleck
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