A 3-digit number has the digits 2,5 and 7.To the nearest hundred, it rounds to 800. What is the answer. Show how you found the answer.
it must be greater than 700, so it is either 725 or 752
so, what do you think?
Thanks
752
To find the answer, we need to determine the possible values for the hundreds digit of the 3-digit number with the given digits 2, 5, and 7.
The given number rounds to 800 to the nearest hundred, which means it is closer to 800 than to any other hundreds place value. This tells us that the tens and units digits don't have a significant impact on rounding to the nearest hundred.
Since the number rounded to 800, the hundreds digit can either be 7 or 8. We'll consider both cases:
Case 1: Hundreds digit is 7
In this case, the number would be 7 _ _, where the blank spaces represent the tens and units digits. Since the tens and units digits can be any of the given digits (2, 5, and 7), we have 3 options for each blank space. So, the number of possible numbers in this case is 3 x 3 = 9.
Case 2: Hundreds digit is 8
In this case, the number would be 8 _ _, and similar to the previous case, we have 3 options for each blank space. Therefore, there are 3 x 3 = 9 possible numbers in this case as well.
Combined, there are 9 + 9 = 18 possible numbers that can be formed using the given digits (2, 5, and 7) with a hundreds place value of either 7 or 8.
So, the answer is 18 possible numbers.