solve this simultaneous equation using substitution method: 5a-2b=14
2a+2b=14
I want to make it clear okay it's 5a - 2b = 14 its the 1st equation then the 2nd says 2a + 2b = 14 so how did u get a = 4🤷how did u solve all this and l don't understand it can u plz make it clear
5a -2b=14, 2a+2b=14 SOLN 7a/7=28/7. a=4
5a-2b =14---(1)
2a +2b =14---(2)
2b cancel 2b because they are the same figure. so it remains only
5a =14
+
2a =14
=7a =28 divide both side by 7
a=4.
This is the end of a. So use
5a-2b=14 to get b.
5a-2b =14
5*(4)-2b=14
20-2b=14
Collect like terms
20-14=2b
6=2b divide both side by 2
b=3.
A=4
B=3.
This equation has been successfully solved in the simplest way, if you can only follow the steps.
To solve this simultaneous equation using the substitution method, we will start by isolating one variable in one of the equations and then substitute it into the other equation.
Let's solve for b in the first equation:
5a - 2b = 14
First, move the term with b to the other side:
-2b = -5a + 14
Divide both sides of the equation by -2 to isolate b:
b = (5a - 14)/2
Now, substitute this expression for b into the second equation:
2a + 2((5a - 14)/2) = 14
Simplify:
2a + 5a - 14 = 14
Combine like terms:
7a - 14 = 14
Add 14 to both sides of the equation:
7a = 28
Divide both sides of the equation by 7 to solve for a:
a = 4
Now that we have the value of a, substitute it back into one of the original equations to solve for b. Let's use the first equation:
5a - 2b = 14
5(4) - 2b = 14
20 - 2b = 14
Subtract 20 from both sides of the equation:
-2b = -6
Divide both sides of the equation by -2 to solve for b:
b = 3
So the solution to the simultaneous equation is a = 4 and b = 3.
Thank you so much
5a + 2b =14
the first equation says that 2b = 5a-14
so use that in the second equation to get
2a+(5a-14) = 14
a=4
so 20-2b=14
b=3