(edited)
Question:
A money box contains only 10-cent
and 20-cent coins. There are 33
coins with a total value of $4.60.
How many coins of each?
No. of 10-cent coins = ?
No. of 20-cent coins = ?
Please help me, it would help a lot.
To solve this problem, we can set up a system of equations based on the given information. Let's use the variables "x" and "y" to represent the number of 10-cent and 20-cent coins, respectively.
We know that there are 33 coins in total, so the first equation is:
x + y = 33
We also know that the total value of the coins is $4.60, which we can represent in cents as:
10x + 20y = 460
Now we have a system of two equations with two variables. To solve it, we can use either substitution or elimination method.
Let's use the substitution method to solve the system. We'll isolate one variable from one equation, and substitute it into the other equation. In this case, let's solve the first equation for x:
x = 33 - y
Now we can substitute this value of x into the second equation:
10(33 - y) + 20y = 460
330 - 10y + 20y = 460
10y = 460 - 330
10y = 130
y = 130 / 10
y = 13
Now that we have the value of y, we can substitute it back into the first equation to find x:
x + 13 = 33
x = 33 - 13
x = 20
So, there are 20 ten-cent coins and 13 twenty-cent coins.