If Susan is at the store and can buy any two fruits (the store sells apples, oranges, pears, bananas, plums and kiwis), how many combinations of fruit can she choose?
Idk its prob 7
The correct answer is actually 15.
To find the number of combinations, we can use the formula nC2, where n is the number of options and 2 is the number of items we are selecting.
So, nC2 = 6C2 = (6!)/(2!(6-2)!) = (6*5)/(2*1) = 15
Therefore, Susan can choose from 15 different combinations of two fruits at the store.
To find the number of combinations of fruit that Susan can choose, we can use the concept of permutations and combinations.
Since Susan can choose any two fruits, we need to find the number of combinations of 2 items out of 6. This can be calculated using the formula for combinations:
nCr = n! / (r! * (n - r)!)
Where n is the total number of items (in this case, the total number of fruits) and r is the number of items to be chosen (in this case, 2).
Let's calculate it step by step:
Step 1: Calculate n!
n! = 6! = 6 * 5 * 4 * 3 * 2 * 1 = 720
Step 2: Calculate r!
r! = 2! = 2 * 1 = 2
Step 3: Calculate (n - r)!
(n - r)! = (6 - 2)! = 4! = 4 * 3 * 2 * 1 = 24
Step 4: Calculate nCr
nCr = 720 / (2 * 24) = 720 / 48 = 15
Therefore, Susan can choose from 15 combinations of fruit.
order doesn't manner ... pear and plum is the same as plum and pear
(6 * 5) / 2 = ?
this result does not count two of the same fruit as a combination