Approximate the area under the curve y = x^2 + 4 from x = 2 to x = 5 using a left sum with 6 subdivisions.

The area is approximately

Whoever helped me earlier, I did solve the equation which gave me 40.2 but the answer was 36.875, idk what I'm doing wrong (this is now a different question)

I don't know how you got 40.2, since you did not deign to show your work.

I got
A = 1/2 (f(2)+f(2.5)+f(3)+f(3.5)+f(4)+f(4.5))
= 1/2 (8 + 10.25 + 13 + 16.25 + 20 + 24.25) = 45.875

Something is wrong with this problem.

All I need is an answer but explanation too please.

To approximate the area under the curve using a left sum with subdivisions, you need to follow these steps:

1. Determine the width of each subdivision: Divide the total interval into equal parts by subtracting the lower limit from the upper limit and then dividing by the number of subdivisions. In this case, you divide (5 - 2) by 6 to get a width of 0.5.

2. Calculate the left endpoints of each subdivision: Start with the lower limit (x = 2) and then increment by the width of each subdivision to get the left endpoints. In this case, the left endpoints would be 2, 2.5, 3, 3.5, 4, and 4.5.

3. Evaluate the function at each left endpoint: Plug in each left endpoint value into the function y = x^2 + 4 to get the corresponding y-values. In this case, the y-values would be 8, 10.25, 13, 16.25, 20, and 24.25.

4. Calculate the sum of the areas: Multiply each width by its corresponding y-value and add them all together. In this case, the sum would be (0.5 * 8) + (0.5 * 10.25) + (0.5 * 13) + (0.5 * 16.25) + (0.5 * 20) + (0.5 * 24.25) = 4 + 5.125 + 6.5 + 8.125 + 10 + 12.125 = 46.875.

Therefore, the approximated area under the curve y = x^2 + 4 from x = 2 to x = 5, using a left sum with 6 subdivisions, is approximately 46.875.