Ask questions and get helpful answers.

Consider the function f (x)=7−6x^2 on the interval [ − 3 , 3 ] . Find the average or mean slope of the function on this interval, i.e.

f(3)-f(-3) / 3-(-3)=

By the Mean Value Theorem, we know there exists a c in the open interval (−3,3) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.

=

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
1 answer
  1. ok, you have the mean slope, which is 0
    So, where is f'(x) = 0?
    f' = -12x
    so f'(0) = 0
    This should all have been clear, since f(x) is a parabola, with x=0 as the axis of symmetry, and the interval [-3,3] has its center there.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    👤
    oobleck

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.