Put the following equation of a line into slope-intercept form simplifying all fractions
12x+9y=18
6x-10y=
6x−10y=
\,\,-40
−40
To put the equation 12x + 9y = 18 into slope-intercept form, which is of the form y = mx + b, follow these steps:
Step 1: Start by isolating the y-term on the left side of the equation.
12x + 9y = 18
Subtract 12x from both sides:
9y = -12x + 18
Step 2: Divide each term by the coefficient of y (9) to isolate y.
y = (-12/9)x + (18/9)
Step 3: Simplify the fractions.
y = (-4/3)x + 2
Therefore, the equation 12x + 9y = 18 in slope-intercept form is y = (-4/3)x + 2.
To put the equation of a line in slope-intercept form, which is in the form y = mx + b, we need to isolate y on one side of the equation.
Let's start by simplifying the equation by subtracting 12x from both sides:
12x + 9y = 18
9y = -12x + 18
Next, we want to get y by itself, so we divide every term by 9:
(9y)/9 = (-12x)/9 + 18/9
y = (-12/9)x + 2
Finally, we can simplify the fraction -12/9 by dividing both numerator and denominator by their greatest common divisor, which is 3:
y = (-4/3)x + 2
So, the equation 12x + 9y = 18, when simplified and written in slope-intercept form, becomes y = (-4/3)x + 2.
we want y = m x + b
9 y = -12 x + 18
y = (-12/9) x + 2
y = -(4/3) x + 2
slope = -4/3
hits y axis at y = 2