What is the total resistance of two 8Ω resistors in parallel?
Show work.
THANK YOU!
the inverse of resistance is conductance
conductance of each = 1/8
in parallel conductance adds
total conductance = 1/8 + 1/8 = 1/4
so resistance = 1/ (1/4) = 4 ohms
or
1/R = 1/R1 + 1/R2 + 1/R3 .....
Why did the resistor go to the parallel park?
Because it couldn't find a series spot!
Now, let's calculate the total resistance of two 8Ω resistors in parallel.
The formula for calculating the total resistance of resistors in parallel is:
1/RTotal = 1/R1 + 1/R2 + ...
So, for two 8Ω resistors in parallel:
1/RTotal = 1/8Ω + 1/8Ω
To simplify this equation, we need a common denominator:
1/RTotal = 1/8Ω + 1/8Ω
= 1/8Ω + 1/8Ω * (8Ω/8Ω)
= 1/8Ω + 1/64Ω
= (8/64Ω + 1/64Ω)
= 9/64Ω
Taking the reciprocal of both sides:
RTotal = 64Ω/9
So, the total resistance of two 8Ω resistors in parallel is approximately 7.11Ω.
You're welcome!
To find the total resistance (Rt) of two resistors in parallel, you can use the formula:
1/Rt = 1/R1 + 1/R2
where R1 and R2 are the resistances of the individual resistors.
Given that both resistors have a resistance of 8Ω, we can substitute the values into the formula:
1/Rt = 1/8Ω + 1/8Ω
To simplify, we can find a common denominator of 8:
1/Rt = (1+1)/8Ω
1/Rt = 2/8Ω
1/Rt = 1/4Ω
To get the value of Rt, we can take the reciprocal of both sides:
Rt = 4Ω
Therefore, the total resistance of two 8Ω resistors in parallel is 4Ω.
To find the total resistance of two resistors in parallel, you need to use the formula:
1/R_total = 1/R1 + 1/R2
where R_total is the total resistance, R1 and R2 are the resistances of the individual resistors.
In this case, since both resistors have a resistance of 8Ω, the equation becomes:
1/R_total = 1/8Ω + 1/8Ω
To simplify the equation, we need to find a common denominator:
1/R_total = (1+1)/8Ω
1/R_total = 2/8Ω
Now, invert both sides of the equation to isolate R_total:
R_total/1 = 8Ω/2
R_total = 4Ω
Therefore, the total resistance of two 8Ω resistors in parallel is 4Ω.