What is the total resistance of two 8Ω resistors in parallel?

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the inverse of resistance is conductance

conductance of each = 1/8
in parallel conductance adds
total conductance = 1/8 + 1/8 = 1/4
so resistance = 1/ (1/4) = 4 ohms

or
1/R = 1/R1 + 1/R2 + 1/R3 .....

Why did the resistor go to the parallel park?

Because it couldn't find a series spot!

Now, let's calculate the total resistance of two 8Ω resistors in parallel.

The formula for calculating the total resistance of resistors in parallel is:

1/RTotal = 1/R1 + 1/R2 + ...

So, for two 8Ω resistors in parallel:

1/RTotal = 1/8Ω + 1/8Ω

To simplify this equation, we need a common denominator:

1/RTotal = 1/8Ω + 1/8Ω
= 1/8Ω + 1/8Ω * (8Ω/8Ω)
= 1/8Ω + 1/64Ω
= (8/64Ω + 1/64Ω)
= 9/64Ω

Taking the reciprocal of both sides:

RTotal = 64Ω/9

So, the total resistance of two 8Ω resistors in parallel is approximately 7.11Ω.

You're welcome!

To find the total resistance (Rt) of two resistors in parallel, you can use the formula:

1/Rt = 1/R1 + 1/R2

where R1 and R2 are the resistances of the individual resistors.

Given that both resistors have a resistance of 8Ω, we can substitute the values into the formula:

1/Rt = 1/8Ω + 1/8Ω

To simplify, we can find a common denominator of 8:

1/Rt = (1+1)/8Ω

1/Rt = 2/8Ω

1/Rt = 1/4Ω

To get the value of Rt, we can take the reciprocal of both sides:

Rt = 4Ω

Therefore, the total resistance of two 8Ω resistors in parallel is 4Ω.

To find the total resistance of two resistors in parallel, you need to use the formula:

1/R_total = 1/R1 + 1/R2

where R_total is the total resistance, R1 and R2 are the resistances of the individual resistors.

In this case, since both resistors have a resistance of 8Ω, the equation becomes:

1/R_total = 1/8Ω + 1/8Ω

To simplify the equation, we need to find a common denominator:

1/R_total = (1+1)/8Ω

1/R_total = 2/8Ω

Now, invert both sides of the equation to isolate R_total:

R_total/1 = 8Ω/2

R_total = 4Ω

Therefore, the total resistance of two 8Ω resistors in parallel is 4Ω.