what is the period of a pendulum if the length of the rope is 1.5 m?
Yes, 2.45567...
So would it be:
T=2pisqrt(L/g)
T=2pisqrt(1.5 m/9.8 N/kg)
T=2.46 s
Is this correct
What is the gravitational force between the two objects, the smaller object has a mass of 0.25kg and the larger object is 0.55m apart?
To determine the period of a pendulum, you need to use the formula:
T = 2π√(L/g)
where T represents the period, L is the length of the pendulum, and g is the acceleration due to gravity.
In this case, the length of the rope is given as 1.5 meters. However, we are missing the value of the acceleration due to gravity, which can vary depending on the location. The average value for g on Earth is approximately 9.8 m/s^2.
So, to calculate the period, you can substitute the given values into the formula:
T = 2π√(1.5/9.8)
Now, we can simplify the equation:
T ≈ 2π√(0.153)
Calculating the square root:
T ≈ 2π * 0.391
Finally, we can compute the result:
T ≈ 2.456 seconds.
Therefore, the period of a pendulum with a rope length of 1.5 meters is approximately 2.456 seconds, assuming an average acceleration due to gravity of 9.8 m/s^2.