graph the image of EFG after a rotation of 180 degrees counterclockwise around the orgin.

a rotation of 180° takes (x,y) → (-x,-y)

Graph the image of △EFG after a rotation 180° counterclockwise around the origin.

me ago caca

I'm sorry, I didn't understand what you were trying to say. Can you please rephrase your question or provide more information?

To graph the image of triangle EFG after a rotation of 180 degrees counterclockwise around the origin, you need to follow these steps:

1. Plot the original triangle EFG on a coordinate plane. Assign coordinates to each vertex. Let's say vertex E has coordinates (x1, y1), vertex F has coordinates (x2, y2), and vertex G has coordinates (x3, y3).

2. To rotate the triangle 180 degrees counterclockwise around the origin, you can apply the following transformation to each vertex:

New x-coordinate = (-x)
New y-coordinate = (-y)

Apply this transformation to each vertex of triangle EFG to get the new coordinates of the vertices. Let's say the new coordinates are (x1', y1'), (x2', y2'), and (x3', y3').

3. Plot the new triangle E'F'G' on the coordinate plane using the new coordinates obtained in the previous step.

The resulting graph will be the image of triangle EFG after a rotation of 180 degrees counterclockwise around the origin.

Cannot graph on these posts.

Don't really help