The concentration of a solution is 284,000 ppm. How many grams of solute is contained in 100 grams of solution?

2.84

Well, if you have 100 grams of solution, that means you have 100 grams of both the solute and the solvent. But wait, there's more! Now let's convert those pesky ppm into grams.

Since 1 ppm is equal to 1 gram per million grams (or 1 milligram per kilogram), we can calculate the grams of solute by multiplying the concentration (284,000 ppm) by the mass of the solvent (100 grams).

So, grab your calculator and let's dive in:

284,000 ppm x 100 grams = 28,400,000 grams.

Voila! There are 28,400,000 grams of solute in 100 grams of solution. That's a whole lot of grams!

To find the grams of solute contained in 100 grams of solution, we need to calculate it using the concentration in parts per million (ppm) and the formula:

Grams of solute = (Concentration in ppm * Weight of solution in grams) / 1,000,000

Substituting the given values:

Grams of solute = (284,000 ppm * 100 g) / 1,000,000

Now we can calculate it:

Grams of solute = (284,000 * 100) / 1,000,000
= 28,400 / 1,000
= 28.4 grams

Therefore, there are 28.4 grams of solute contained in 100 grams of solution.

To calculate the grams of solute in 100 grams of solution, we first need to convert the concentration from parts per million (ppm) to grams per gram (g/g) or grams per liter (g/L). However, since we are given the concentration in ppm and not the specific solute, we cannot convert it directly to g/g or g/L without additional information.

To proceed, we need to assume that the concentration is referring to the solute dissolved in a liquid (usually water). We can then convert ppm to g/L by using the formula:

ppm = (mass of solute / volume of solution) * 10^6

In this case, assuming the volume of the solution is 1 liter (1000 grams), we can rearrange the formula to solve for the mass of solute:

mass of solute = (ppm * volume of solution) / 10^6

Substituting the given values:
- ppm = 284,000
- volume of solution = 100 grams (assuming 100 mL = 100 grams for water)

mass of solute = (284,000 * 100) / 10^6
mass of solute = 28.4 grams

Therefore, 100 grams of the solution contains 28.4 grams of solute.

I assume that is 284,000 ppm w/w. It could be w/v; w/w; v/v.

1 ppm w/w = 1 mg/kg. That's a good factor to remember.
So you have 28,000 mg/1000 g solution.
28,000 mg x (100 g/1000 g) = 2800 mg/100 g solution and that's 2.800 grams of solute.