A man whose mass is 10kg stands on a spring weighing machine inside an elevator.what's the reading of the weighing machine when the elevator starts to ascend with an acceleration 2m\s
F = ma
weight due to
gravity: 10g
elevator: 10*2
so, what do you think?
Sorry the weight is 80kg.
M(g+a)
80(10+2)
=960
Buh the problem is that the correct answer is 96
And it's seem confusing
If the mass is 80, the force on the scale is about 960 Newtons, not 96
M(g+a)
80(10+2)
960
960÷10
=96kg
It's force so we'll divide by 10 so as to make the answer KG
Please I need this solved as soon as possible
To determine the reading on the weighing machine, we need to consider the forces acting on the man when the elevator starts to ascend.
When the elevator accelerates upwards, there are two main forces acting on the man:
1. The gravitational force pulling him downwards, given by the formula F_gravitational = mass * acceleration due to gravity = 10 kg * 9.8 m/s^2 = 98 N.
2. The normal force exerted by the spring weighing machine upward, which counteracts the gravitational force.
In an accelerating elevator, the normal force is modified due to the acceleration. It can be calculated as follows:
F_net = m * a
F_net = mass * (acceleration due to gravity + elevator's acceleration)
F_net = 10 kg * (9.8 m/s^2 + 2 m/s^2)
F_net = 10 kg * 11.8 m/s^2
F_net = 118 N
Therefore, the reading on the weighing machine when the elevator starts to ascend with an acceleration of 2 m/s^2 will be 118 N.