when the angle of elevation of the sun is 58degrees a vertical pole casts a shadow of length 5m on a horizontal ground .find the height of the pole

tan(58º) = pole / 5 m

yes now

iam waiting for an answere

9.5m

Unable to solve

To find the height of the pole, we can use trigonometry and the concept of similar triangles.

Let's denote the height of the pole as "h" (in meters) and the length of the shadow as "s" (in meters). The angle of elevation of the sun is given as 58 degrees.

We can first identify two right triangles involved in the problem.

1. The first triangle consists of the vertical pole, its height (h), the length of the shadow (s), and the angle of elevation (58 degrees).

2. The second triangle consists of the vertical pole, its height (h), and a line perpendicular to the ground (let's denote it as "y").

Now, we can set up the following equation using the tangent function:

tan(58) = h / s

Alternatively, we can rewrite it as:

h = s * tan(58)

Plugging in the values into the equation, we get:

h = 5 * tan(58)

Using a calculator, you can find that tan(58) is approximately 1.6643.

Therefore, the height of the pole is:

h ≈ 5 * 1.6643 ≈ 8.3215 meters

So, the height of the pole is approximately 8.3215 meters.