Find the polynomial function f with Real coefficients that has the given degree 3 zeros 2, 1sqrt 2i, and solution point 42
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1 answer

since complex roots come in conjugate pairs,
f(x) = a(x+2)(x(1i√2))(x(1+i√2))
= a(x+2)((x1)^2+2)
Not sure what a "solution point" is, since you have already given the roots.
But if f(0) = 42, then
a(2)(1+2) = 42
a = 7
and f(x) = 7(x+2)(x^22x+3)
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