Ask questions and get helpful answers.

Find the polynomial function f with Real coefficients that has the given degree 3 zeros -2, 1-sqrt 2i, and solution point -42

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

1 answer

  1. since complex roots come in conjugate pairs,
    f(x) = a(x+2)(x-(1-i√2))(x-(1+i√2))
    = a(x+2)((x-1)^2+2)
    Not sure what a "solution point" is, since you have already given the roots.
    But if f(0) = 42, then
    a(2)(1+2) = 42
    a = 7
    and f(x) = 7(x+2)(x^2-2x+3)

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.