A 28/32-inch hole must be enlarged to 58/64 inch to insert a bushing. How much wider than the original hole will the hole be?
58/64 - 56/64 = ___
To find out how much wider than the original hole the enlarged hole will be, we need to subtract the width of the original hole from the width of the enlarged hole.
Given that the original hole is 28/32 inch and the enlarged hole is 58/64 inch, we can simplify both fractions to have a common denominator of 64.
28/32 inch can be simplified to (28/32) * (2/2) = 56/64 inch.
Now we can subtract 56/64 inch from 58/64 inch:
(58/64) - (56/64) = 2/64 inch.
Since the question asks for the width difference in terms of "wider," the answer is:
The hole will be 2/64 inch wider than the original hole.
To determine how much wider the hole will be after it is enlarged, we need to find the difference between the final size and the original size of the hole.
The original hole size is 28/32 inch, which can be simplified to 7/8 inch by dividing both the numerator and denominator by 4.
Next, we need to convert the final size of the hole to a common denominator. Both 58 and 64 are divisible by 2, so we can divide them both by 2. This gives us a final size of 29/32 inch.
Now we can find the difference between the final size and the original size of the hole:
Final size - Original size = 29/32 - 7/8
To perform this subtraction, we need a common denominator. The least common multiple of 8 and 32 is 32, so we can use that as the common denominator.
Converting both fractions to have a denominator of 32, we get:
(29/32) - (28/32) = 1/32
So, the hole will be 1/32 inch wider than the original size.