While lifting a load of 200N using lever an effort of 80N moved through a distance of 20cm to lift the load through a distance

work in = F * d = 80 N * 0.20 meters = 16 Joules

if all is perfect work out = work in
200 N * h = 16
h = 0.08 meters = 8 centimeters

White lifting a load of 200N using aload an effort of 80N moved through a distance of 20cm to lift a load through a distance of 4cm to calculate (a) mechanical advantage and velocity ratio

I dont now

To find the distance through which the load is lifted, we can use the concept of work. Work is calculated by multiplying the force applied by the distance over which it is applied. In this case, the effort force is 80N and it is applied over a distance of 20cm.

To calculate the work done by the effort force, we can use the formula:

Work = Force × Distance

Substituting the given values, we have:

Work = 80N × 20cm

Notice that we need to convert the distance from centimeters to meters, as the SI unit for work is the Newton meter (Nm). Thus, we have:

Work = 80N × 0.2m
= 16 Nm

Now, since work is done by the effort force, it is equal to the work done on the load. Therefore, the work done on the load can be calculated as 16 Nm.

To find the distance through which the load is lifted, we can rearrange the formula for work:

Work = Force × Distance

Dividing both sides of the equation by force, we have:

Distance = Work / Force

Using the calculated values, we can substitute them into the formula:

Distance = 16 Nm / 200N
= 0.08m

So, the distance through which the load is lifted is 0.08m (or equivalently, 8cm).

Solution of this question

I confused. what the question?