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A sample of gas is collected over water at a temperature of 45.0 oC when barometric pressure reading is 742.0 torr. What is the partial pressure of the dry gas?

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2 answers
  1. This site tells me that vapour pressure of water at 35.0 ∘C = 42.2⋅mm⋅Hg.
    Explanation:
    P
    collected
    =P gas+P SVP, P SVP is given above, and is called the saturated vapour pressure. This should have been quoted with the question.

    Thus
    Pgas≅700⋅mm⋅Hg.

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  2. Ptotal = Pgas + PH2O.
    Ptotal = 742.0
    pH2O = ? Look up the vapor pressure of H2O @ 45.0 degrees C. You should have that in your text/notes or you can find it on the web. Note that Helper used 35.0 but the problem gives 45.0 C.

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    DrBob222

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